\[K = \frac {[\mathrm{Br_2}][\mathrm{Cl_2}]}{[\mathrm{BrCl}]^2} = \frac {0,15\mathrm{M} \cdot 0,15\mathrm{M}}{(0,22\mathrm{M})^2} = 0,46487603 ≈ 046\]
A28
\[K = \frac {[\mathrm{Br_2}][\mathrm{Cl_2}]}{[\mathrm{BrCl}]^2} = \frac {0,15\mathrm{M} \cdot 0,15\mathrm{M}}{(0,22\mathrm{M})^2} = 0,46487603 ≈ 046\]
